Mathematics
TanjaAcebedo
2015-11-04 11:18:06
Factor completely 16a^3b^7 + 2a^6 b4 − 22a ^4 b^5. 2(8a3b7 + a6b4 − 11a4b5) 2a3b4(8b3 + a3 − 11ab) a3b4(16b3 + 2a3 − 22ab) 8b3 + a3 − 11ab
ANSWERS
rosado
2015-11-04 13:21:21

factor out 2a^3 from the epression  so it would become 2a^3b(8b^6 + a^3 * 4 - 11ab^4) then you would use the communitive property to re order the terms  so your answer is  2a^3b * (8b^6 + 4a^3 - 11ab^4)

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