f(n)=10(1.02)^n f(n)=a1(r)^n a1=10, initial value r=1.02, or 2% increase Part A.) (9.5,11.5) would be reasonable as the initial point is 10 and the final point is 11.04. You could also begin at 10 and end at 11.1, if wanting to maximize space used. Part B.) Y-intercept, here being 10, represents the starting point, or initial value, of the height of the plant. Part C.) ARC: (f(5)-f(1))/(5-1) f(5)=11.04080803 f(1)=10.2 (11.04080803-10.2)/(5-1) (0.84080832)/(4)=0.210202008 cm/n, growth of 0.210202008 cm per n day of growth

A)[latex]11.04 = 10(1.02)^n 1.104 = 1.02^n [/latex] [latex]1.104 = 1.02^n~ 1.104 = 1.02 n = 1.104/ ln 1.02 n = 4.99630409516 [/latex] 4.99 when rounded B. [latex]f(0) = 10(1.02)^0 f(0) = 10(1) f(0) = 10 [/latex] C.[latex]f(1) = 10(1.02)^1 f(1) = 10(1.02) f(1) = 10.2 (1, 10.2) f(5) = 10(1.02)^5 f(5) = 10(1.1040808) f(5) = 11.040808 (5, 11.040808) [/latex]