Mathematics
JannieDoi
2016-09-29 10:02:21
Rectangle A is similar to rectangle B. Rectangle B has sides that are 4 times longer than rectangle A. What is the relationship between the perimeters of rectangles A and B A. The perimeter of rectangle A is equal to the perimeter of rectangle B. B. The perimeter of rectangle B is 4 times the perimeter of rectangle A. C. The perimeter of rectangle B is 8 times the perimeter of rectangle A. D. The perimeter of rectangle B is one-fourth the perimeter of rectangle A.
ANSWERS
wella
2016-09-29 11:58:02

The answer is option B.  let the sides of rectangle A be x and y so the sides of rectangle B will be 4x and 4y perimeter of recyangle A= 2(l+b)                                            =2(x+y)                                            =2x+2y perimeter of rectangle B=2(l+b)                                           = 2(4x+4y)                                           =2*4(x+y)                                           = 8 (x+y) Therefore their ratio= 8(x+y) / 2(x+y)                                   =4/1 Therefore Perimeter of rectangle B is 4 times perimeter of rectangleA Hope I helped!

Deter556
2016-09-29 11:59:17

B.The perimeter of rectangle b  is 4 times the perimeter of rectangle a.

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