Mathematics
12lball
2016-09-24 10:58:21
the perimeter of a rectangle is twice the sum of its length and its width. the perimeter is 40 meters and its length is 2 meters more than its width what is the length
ANSWERS
desire234
2016-09-24 13:17:20

1).- P = 2(W + L)-------------OR-------------- P= 2W +2L (distributing)  where: p= perimeter w= width l= length  They tell you that "the length is 2 meters more than twice it width"  2).- L = 2 + 2W  If we substitute (2) in (1), then:  P = 2W + 2 ( 2 + 2W) P = 2W + 4 + 4W P = 6W + 4  We also know that the perimeter is 40 meters, so:P = 40 = 6W + 4 Solving for W, you get:  40 = 6W + 4 36 = 6W  W = 6.  But we want to know what L equals. We go back to equation 2 and subtitue W =6.  L = 2 + 2(6)  L= 14  WHICH IS TRUE..  P = 2(6) + 2 (14) P = 12 + 28 P = 40

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