the perimeter of a rectangle is twice the sum of its length and its width. the perimeter is 40 meters and its length is 2 meters more than its width what is the length

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2016-09-24 13:17:20

1).- P = 2(W + L)-------------OR-------------- P= 2W +2L (distributing) where: p= perimeter w= width l= length They tell you that "the length is 2 meters more than twice it width" 2).- L = 2 + 2W If we substitute (2) in (1), then: P = 2W + 2 ( 2 + 2W) P = 2W + 4 + 4W P = 6W + 4 We also know that the perimeter is 40 meters, so:P = 40 = 6W + 4 Solving for W, you get: 40 = 6W + 4 36 = 6W W = 6. But we want to know what L equals. We go back to equation 2 and subtitue W =6. L = 2 + 2(6) L= 14 WHICH IS TRUE.. P = 2(6) + 2 (14) P = 12 + 28 P = 40

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