Physics
mayralol
2016-09-23 08:08:36
A skydiver is jumping from an airplane traveling at 10.0 m/s. The plane is 3520 m above the earth. The sky diver pulls his cord at 1760 m above the earth. Neglecting air resistance, how far does the skydiver travel horizontally before pulling the cord? x=____ a.3590m b.134m c.190m
ANSWERS
juliepalmer
2016-09-23 12:53:10

Given: velocity = 10.0 m/s. The plane is 3520 m above the earth. The sky diver pulls his cord at 1760 m above the earth. gravity = 9.8 m/s² Δheight = initial height - final height = gt²/2  time =√(2 • Δh/g)  time =√{2 • (3520-1760)/9.8} time =√{2 * 179.59 s² time = √359.18 time = 18.95 s.  s=vt=10•18.95=189.5m or 190m The skydiver traveled 190m horizontally before pulling the cord.

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