Mathematics
Lavera931
2016-09-23 05:35:51
How do you solve 8e^4x+8=15 using natural log with e? Thank you!
ANSWERS
eyespotter
2016-09-23 10:46:53

[latex] 8e^{4x+8}= 15\ e^{4x+8}=dfrac{15}{8}\ 4x+8=ln dfrac{15}{8}\ 4x=ln dfrac{15}{8}-8\ x=dfrac{1}{4}ln dfrac{15}{8}-2[/latex]

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