Mathematics
winfreddon
2016-09-21 06:12:21
What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3?
ANSWERS
meowmeow8083
2016-09-21 10:18:52

a = U1 = 6r = 1/3U2 = a.r = 6.1/3 = 2U3 = a.r^n-1 = 6.1/3^2 = 6.1/9 = 2/3U4 = a.r^n-1 = 6.1/3^3 = 6.1/27 = 2/9U5 = a.r^n-1 = 6.1/3^4 = 6.1/81 = 2/27 the sum6 + 2 + 2/3 + 2/9 + 2/27 = 8 + 26/27 = 242/27 = 8,9629

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