I figured this out by dividing 201 by three, and then added two of the parts together. Now I have two parts, and one of them is twice as large as the other. So basically 201÷3, which is 67, and then 67+67 (or 67×2) which is 134. The ages of the buildings are 67 and 134.
The total ages of 2 buildings is 201 years. if one building is twice as old as the other, what are the ages of 2 buildings?