Cacasuperman
2021-05-05 00:40:36
For the function f(x) = –(x 1)^2 + 4, identify the vertex, domain, and range. a. The vertex is (–1, 4), the domain is all real numbers, and the range is y ≥ 4. b. The vertex is (–1, 4), the domain is all real numbers, and the range is y ≤ 4. c. The vertex is (1, 4), the domain is all real numbers, and the range is y ≥ 4. d. The vertex is (1, 4), the domain is all real numbers, and the range is y ≤ 4.
ANSWERS
tutuho2002
2021-05-05 06:56:09

the vertex is at -b/(2A). if you use the foil method it will come out to -(x^2+2x+1)+4. then distribute the negative and simplify the equation (add the four) the equation comes out to be -x^2-2x+3. The vertex is at x=2/(2*-1), which is -1. plug -1 into the original equation to find y, (y=-(-1)^2-2*(-1)+3) which is y=4. so the vertex is at (-1,4). then since the parabola opens down (negative a value) and has a maximum at 4, y is always less than or equal to 4. x is all real numbers as it goes on forever. so b is your answer.

Emmie654
2021-05-05 06:57:24

[latex]f(x) = a(x-p)^{2} +q \ \ W=(p,q)[/latex] ==================== [latex]f(x) = -(x+1)^{2} +4 \ \ W=(-1,4)[/latex] ------------------------------------------ [latex]D: x in R[/latex] -------------------------------------------- [latex]a extless 0 \ \ R: y leq 4[/latex]

ADD ANSWER