Mathematics
Nicomandel11
2016-04-18 10:10:51
F(x)=x^3+x^2-42x what are the zeros
ANSWERS
Burden196
2016-04-18 12:01:01

F(x)=x^3+x^2-42x Roots  Solve for x over the real numbers x³+x²-42x=0 Factor the left-hand side    The left-hand side factors into a product with three terms x(x-6)(x+7)=0 Find the roots of each term separately  Split into three equations x-6=0  x=0  x+7=0 Look at the first equation and solve for x  Add 6 to both sides x=6  x=0 x+7=0 Look at the third equation and solve for x  Subtract 7 from both sides Answer: x=6    x=0  x=-7

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