Mathematics
caseysandy318
2016-04-17 03:02:36
Which are the solutions of x2 = 19x + 1?
ANSWERS
warrenbisch
2016-04-17 04:28:25

[latex]x^2=19x+1 \ x^2 -19x-1=0 \ x= frac{19б sqrt{(-19)^2-4*1*(-1)} }{2*1}= frac{19б sqrt{361+4} }{2}= frac{19б sqrt{365} }{2}[/latex]

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