A mixture of
12%
disinfectant solution is to be made from
10%
and
17%
disinfectant solution. How much of each solution should be used if
28
gallons of the
12%
solution are needed?

ANSWERS

2016-04-16 10:52:46

Set up a system of 2 equations. Gallon equation: x+y = 28 Solution equation: 10x + 17y = (28)(12) Solve with substitution: y = 28-x (From 1st equation) (Sub into 2nd equation) 10x + 17(28-x) = 336 10x + 476 - 17x = 336 -7x = -140 x = 20 y = 28-20 = 8 Therefore the solution is (20,8) You need 20 gal of 10% solution mixed with 8 gal of 17% solution to obtain 28 gal of 12% solution.

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