Two endpoints of the diagonal of a parallelogram are k(0,3) and l(4,1). what is the length of the diagonal

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2016-04-14 14:01:11

distance = sqrt (x2 - x1)^2 + (y2 - y1)^2 (0,3).....x1 = 0 and y1 = 3 (4,1)....x2 = 4 and y2 = 1 now we sub and solve d = sqrt (4 - 0)^2 + 1 - 3)^2 d = sqrt (4^2) + (-2^2) d = sqrt (16 + 4) d = sqrt 20 d = 4.472 <==

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