We can set up 2 equations given the information. Let the price of advance ticket be represented by A and same day ticket by S A + S = 50 20A + 40S = 1700 Solve for A in the first equation by subtracting S on both sides. U will get A = 50 - S Now substitute 50 - S for A in the second equation. 20 (50 - S) + 40S = 1700 1000 - 20S + 40S = 1700 20S = 700 S = 35 Same day ticket costs $35 and advance ticket costs $15
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $50 . For one performance, 20 advance tickets and 40 same-day tickets were sold. The total amount paid for the tickets was $1700 . What was the price of each kind of ticket?