write the equation of the line perpendicular to y= 2/5x+6/6 that passes through the point (-2,6)

ANSWERS

2016-04-11 06:53:40

the line to find: y = mx + b the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1 thus the slope m = -5/2 the line passes through the point (-2,6) so: 6 = (-5/2)×(-2) + b so b = 1 the equation of the line is y = -5/2x +1

ADD ANSWER