PART A The value of car A decreases by 6000 every year. Since the decrease is the same every year, the function is linear The value of car B decreases by the ratio of [latex] frac{17}{20} [/latex] every year. Since the decrease is by the same ratio every year, the function is exponential PART B Car 1: the function is [latex]y=-6000x+44000[/latex], where [latex]y[/latex] is the value after [latex]x[/latex] years. Negative 6000 shows the decrease every year and 44000 is the value of the car in Year 0 Car 2: the function is [latex]y=(38000) ( frac{17}{20}) ^{x-1} [/latex], where [latex]y[/latex] is the value after [latex]x[/latex] years. 38000 is the value of the car after Year 1 and [latex] frac{17}{20} [/latex] is the ratio of depreciation PART C Value of car 1 after 6 years is [latex]-6000(6)+44000=8000[/latex] Value of car 2 after 6 years is [latex](38000) ( frac{17}{20}) ^{6-1} =16860.8[/latex] There is a significant difference in the values of the cars after 6 years

Autumn is thinking about buying a car. The table below shows the projected value of two different cars for three years.
Number of years 1 2 3
Car 1 (value in dollars) 38,000 32,000 26,000
Car 2 (value in dollars) 38,000 32,300 27,455
Part A: What type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? Explain your answer. (2 points)
Part B: Write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points)
Part C: Autumn wants to purchase a car that would have the greatest value in 6 years. Will there be any significant difference in the value of either car after 6 years? Explain your answer, and show the value of each car after 6 years. (4 points)

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2016-04-09 13:43:38

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